3.1838 \(\int \frac{\sqrt{1-2 x} (2+3 x)^5}{(3+5 x)^2} \, dx\)

Optimal. Leaf size=133 \[ -\frac{\sqrt{1-2 x} (3 x+2)^5}{5 (5 x+3)}+\frac{11}{75} \sqrt{1-2 x} (3 x+2)^4+\frac{64 \sqrt{1-2 x} (3 x+2)^3}{2625}-\frac{172 \sqrt{1-2 x} (3 x+2)^2}{3125}-\frac{4 \sqrt{1-2 x} (3625 x+10998)}{15625}-\frac{328 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{15625 \sqrt{55}} \]

[Out]

(-172*Sqrt[1 - 2*x]*(2 + 3*x)^2)/3125 + (64*Sqrt[1 - 2*x]*(2 + 3*x)^3)/2625 + (11*Sqrt[1 - 2*x]*(2 + 3*x)^4)/7
5 - (Sqrt[1 - 2*x]*(2 + 3*x)^5)/(5*(3 + 5*x)) - (4*Sqrt[1 - 2*x]*(10998 + 3625*x))/15625 - (328*ArcTanh[Sqrt[5
/11]*Sqrt[1 - 2*x]])/(15625*Sqrt[55])

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Rubi [A]  time = 0.0479381, antiderivative size = 133, normalized size of antiderivative = 1., number of steps used = 7, number of rules used = 5, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.208, Rules used = {97, 153, 147, 63, 206} \[ -\frac{\sqrt{1-2 x} (3 x+2)^5}{5 (5 x+3)}+\frac{11}{75} \sqrt{1-2 x} (3 x+2)^4+\frac{64 \sqrt{1-2 x} (3 x+2)^3}{2625}-\frac{172 \sqrt{1-2 x} (3 x+2)^2}{3125}-\frac{4 \sqrt{1-2 x} (3625 x+10998)}{15625}-\frac{328 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{15625 \sqrt{55}} \]

Antiderivative was successfully verified.

[In]

Int[(Sqrt[1 - 2*x]*(2 + 3*x)^5)/(3 + 5*x)^2,x]

[Out]

(-172*Sqrt[1 - 2*x]*(2 + 3*x)^2)/3125 + (64*Sqrt[1 - 2*x]*(2 + 3*x)^3)/2625 + (11*Sqrt[1 - 2*x]*(2 + 3*x)^4)/7
5 - (Sqrt[1 - 2*x]*(2 + 3*x)^5)/(5*(3 + 5*x)) - (4*Sqrt[1 - 2*x]*(10998 + 3625*x))/15625 - (328*ArcTanh[Sqrt[5
/11]*Sqrt[1 - 2*x]])/(15625*Sqrt[55])

Rule 97

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Simp[((a + b
*x)^(m + 1)*(c + d*x)^n*(e + f*x)^p)/(b*(m + 1)), x] - Dist[1/(b*(m + 1)), Int[(a + b*x)^(m + 1)*(c + d*x)^(n
- 1)*(e + f*x)^(p - 1)*Simp[d*e*n + c*f*p + d*f*(n + p)*x, x], x], x] /; FreeQ[{a, b, c, d, e, f}, x] && LtQ[m
, -1] && GtQ[n, 0] && GtQ[p, 0] && (IntegersQ[2*m, 2*n, 2*p] || IntegersQ[m, n + p] || IntegersQ[p, m + n])

Rule 153

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_)*((e_.) + (f_.)*(x_))^(p_)*((g_.) + (h_.)*(x_)), x_Symb
ol] :> Simp[(h*(a + b*x)^m*(c + d*x)^(n + 1)*(e + f*x)^(p + 1))/(d*f*(m + n + p + 2)), x] + Dist[1/(d*f*(m + n
+ p + 2)), Int[(a + b*x)^(m - 1)*(c + d*x)^n*(e + f*x)^p*Simp[a*d*f*g*(m + n + p + 2) - h*(b*c*e*m + a*(d*e*(
n + 1) + c*f*(p + 1))) + (b*d*f*g*(m + n + p + 2) + h*(a*d*f*m - b*(d*e*(m + n + 1) + c*f*(m + p + 1))))*x, x]
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, n, p}, x] && GtQ[m, 0] && NeQ[m + n + p + 2, 0] && IntegerQ[m]

Rule 147

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_) + (f_.)*(x_))*((g_.) + (h_.)*(x_)), x_Symbol]
:> -Simp[((a*d*f*h*(n + 2) + b*c*f*h*(m + 2) - b*d*(f*g + e*h)*(m + n + 3) - b*d*f*h*(m + n + 2)*x)*(a + b*x)^
(m + 1)*(c + d*x)^(n + 1))/(b^2*d^2*(m + n + 2)*(m + n + 3)), x] + Dist[(a^2*d^2*f*h*(n + 1)*(n + 2) + a*b*d*(
n + 1)*(2*c*f*h*(m + 1) - d*(f*g + e*h)*(m + n + 3)) + b^2*(c^2*f*h*(m + 1)*(m + 2) - c*d*(f*g + e*h)*(m + 1)*
(m + n + 3) + d^2*e*g*(m + n + 2)*(m + n + 3)))/(b^2*d^2*(m + n + 2)*(m + n + 3)), Int[(a + b*x)^m*(c + d*x)^n
, x], x] /; FreeQ[{a, b, c, d, e, f, g, h, m, n}, x] && NeQ[m + n + 2, 0] && NeQ[m + n + 3, 0]

Rule 63

Int[((a_.) + (b_.)*(x_))^(m_)*((c_.) + (d_.)*(x_))^(n_), x_Symbol] :> With[{p = Denominator[m]}, Dist[p/b, Sub
st[Int[x^(p*(m + 1) - 1)*(c - (a*d)/b + (d*x^p)/b)^n, x], x, (a + b*x)^(1/p)], x]] /; FreeQ[{a, b, c, d}, x] &
& NeQ[b*c - a*d, 0] && LtQ[-1, m, 0] && LeQ[-1, n, 0] && LeQ[Denominator[n], Denominator[m]] && IntLinearQ[a,
b, c, d, m, n, x]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rubi steps

\begin{align*} \int \frac{\sqrt{1-2 x} (2+3 x)^5}{(3+5 x)^2} \, dx &=-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}+\frac{1}{5} \int \frac{(13-33 x) (2+3 x)^4}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=\frac{11}{75} \sqrt{1-2 x} (2+3 x)^4-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}-\frac{1}{225} \int \frac{(2+3 x)^3 (-180+192 x)}{\sqrt{1-2 x} (3+5 x)} \, dx\\ &=\frac{64 \sqrt{1-2 x} (2+3 x)^3}{2625}+\frac{11}{75} \sqrt{1-2 x} (2+3 x)^4-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}+\frac{\int \frac{(2+3 x)^2 (8568+10836 x)}{\sqrt{1-2 x} (3+5 x)} \, dx}{7875}\\ &=-\frac{172 \sqrt{1-2 x} (2+3 x)^2}{3125}+\frac{64 \sqrt{1-2 x} (2+3 x)^3}{2625}+\frac{11}{75} \sqrt{1-2 x} (2+3 x)^4-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}-\frac{\int \frac{(-558432-913500 x) (2+3 x)}{\sqrt{1-2 x} (3+5 x)} \, dx}{196875}\\ &=-\frac{172 \sqrt{1-2 x} (2+3 x)^2}{3125}+\frac{64 \sqrt{1-2 x} (2+3 x)^3}{2625}+\frac{11}{75} \sqrt{1-2 x} (2+3 x)^4-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}-\frac{4 \sqrt{1-2 x} (10998+3625 x)}{15625}+\frac{164 \int \frac{1}{\sqrt{1-2 x} (3+5 x)} \, dx}{15625}\\ &=-\frac{172 \sqrt{1-2 x} (2+3 x)^2}{3125}+\frac{64 \sqrt{1-2 x} (2+3 x)^3}{2625}+\frac{11}{75} \sqrt{1-2 x} (2+3 x)^4-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}-\frac{4 \sqrt{1-2 x} (10998+3625 x)}{15625}-\frac{164 \operatorname{Subst}\left (\int \frac{1}{\frac{11}{2}-\frac{5 x^2}{2}} \, dx,x,\sqrt{1-2 x}\right )}{15625}\\ &=-\frac{172 \sqrt{1-2 x} (2+3 x)^2}{3125}+\frac{64 \sqrt{1-2 x} (2+3 x)^3}{2625}+\frac{11}{75} \sqrt{1-2 x} (2+3 x)^4-\frac{\sqrt{1-2 x} (2+3 x)^5}{5 (3+5 x)}-\frac{4 \sqrt{1-2 x} (10998+3625 x)}{15625}-\frac{328 \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{15625 \sqrt{55}}\\ \end{align*}

Mathematica [A]  time = 0.0692084, size = 73, normalized size = 0.55 \[ \frac{\frac{55 \sqrt{1-2 x} \left (1181250 x^5+3864375 x^4+4760100 x^3+2225760 x^2-1133340 x-862072\right )}{5 x+3}-2296 \sqrt{55} \tanh ^{-1}\left (\sqrt{\frac{5}{11}} \sqrt{1-2 x}\right )}{6015625} \]

Antiderivative was successfully verified.

[In]

Integrate[(Sqrt[1 - 2*x]*(2 + 3*x)^5)/(3 + 5*x)^2,x]

[Out]

((55*Sqrt[1 - 2*x]*(-862072 - 1133340*x + 2225760*x^2 + 4760100*x^3 + 3864375*x^4 + 1181250*x^5))/(3 + 5*x) -
2296*Sqrt[55]*ArcTanh[Sqrt[5/11]*Sqrt[1 - 2*x]])/6015625

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Maple [A]  time = 0.01, size = 81, normalized size = 0.6 \begin{align*}{\frac{27}{200} \left ( 1-2\,x \right ) ^{{\frac{9}{2}}}}-{\frac{8829}{7000} \left ( 1-2\,x \right ) ^{{\frac{7}{2}}}}+{\frac{107109}{25000} \left ( 1-2\,x \right ) ^{{\frac{5}{2}}}}-{\frac{144681}{25000} \left ( 1-2\,x \right ) ^{{\frac{3}{2}}}}+{\frac{6}{3125}\sqrt{1-2\,x}}+{\frac{2}{78125}\sqrt{1-2\,x} \left ( -2\,x-{\frac{6}{5}} \right ) ^{-1}}-{\frac{328\,\sqrt{55}}{859375}{\it Artanh} \left ({\frac{\sqrt{55}}{11}\sqrt{1-2\,x}} \right ) } \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((2+3*x)^5*(1-2*x)^(1/2)/(3+5*x)^2,x)

[Out]

27/200*(1-2*x)^(9/2)-8829/7000*(1-2*x)^(7/2)+107109/25000*(1-2*x)^(5/2)-144681/25000*(1-2*x)^(3/2)+6/3125*(1-2
*x)^(1/2)+2/78125*(1-2*x)^(1/2)/(-2*x-6/5)-328/859375*arctanh(1/11*55^(1/2)*(1-2*x)^(1/2))*55^(1/2)

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Maxima [A]  time = 2.51594, size = 132, normalized size = 0.99 \begin{align*} \frac{27}{200} \,{\left (-2 \, x + 1\right )}^{\frac{9}{2}} - \frac{8829}{7000} \,{\left (-2 \, x + 1\right )}^{\frac{7}{2}} + \frac{107109}{25000} \,{\left (-2 \, x + 1\right )}^{\frac{5}{2}} - \frac{144681}{25000} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} + \frac{164}{859375} \, \sqrt{55} \log \left (-\frac{\sqrt{55} - 5 \, \sqrt{-2 \, x + 1}}{\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}}\right ) + \frac{6}{3125} \, \sqrt{-2 \, x + 1} - \frac{\sqrt{-2 \, x + 1}}{15625 \,{\left (5 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^5*(1-2*x)^(1/2)/(3+5*x)^2,x, algorithm="maxima")

[Out]

27/200*(-2*x + 1)^(9/2) - 8829/7000*(-2*x + 1)^(7/2) + 107109/25000*(-2*x + 1)^(5/2) - 144681/25000*(-2*x + 1)
^(3/2) + 164/859375*sqrt(55)*log(-(sqrt(55) - 5*sqrt(-2*x + 1))/(sqrt(55) + 5*sqrt(-2*x + 1))) + 6/3125*sqrt(-
2*x + 1) - 1/15625*sqrt(-2*x + 1)/(5*x + 3)

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Fricas [A]  time = 1.59659, size = 263, normalized size = 1.98 \begin{align*} \frac{1148 \, \sqrt{55}{\left (5 \, x + 3\right )} \log \left (\frac{5 \, x + \sqrt{55} \sqrt{-2 \, x + 1} - 8}{5 \, x + 3}\right ) + 55 \,{\left (1181250 \, x^{5} + 3864375 \, x^{4} + 4760100 \, x^{3} + 2225760 \, x^{2} - 1133340 \, x - 862072\right )} \sqrt{-2 \, x + 1}}{6015625 \,{\left (5 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^5*(1-2*x)^(1/2)/(3+5*x)^2,x, algorithm="fricas")

[Out]

1/6015625*(1148*sqrt(55)*(5*x + 3)*log((5*x + sqrt(55)*sqrt(-2*x + 1) - 8)/(5*x + 3)) + 55*(1181250*x^5 + 3864
375*x^4 + 4760100*x^3 + 2225760*x^2 - 1133340*x - 862072)*sqrt(-2*x + 1))/(5*x + 3)

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Sympy [A]  time = 126.374, size = 226, normalized size = 1.7 \begin{align*} \frac{27 \left (1 - 2 x\right )^{\frac{9}{2}}}{200} - \frac{8829 \left (1 - 2 x\right )^{\frac{7}{2}}}{7000} + \frac{107109 \left (1 - 2 x\right )^{\frac{5}{2}}}{25000} - \frac{144681 \left (1 - 2 x\right )^{\frac{3}{2}}}{25000} + \frac{6 \sqrt{1 - 2 x}}{3125} - \frac{44 \left (\begin{cases} \frac{\sqrt{55} \left (- \frac{\log{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} - 1 \right )}}{4} + \frac{\log{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} + 1 \right )}}{4} - \frac{1}{4 \left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} + 1\right )} - \frac{1}{4 \left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} - 1\right )}\right )}{605} & \text{for}\: x \leq \frac{1}{2} \wedge x > - \frac{3}{5} \end{cases}\right )}{15625} + \frac{326 \left (\begin{cases} - \frac{\sqrt{55} \operatorname{acoth}{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} \right )}}{55} & \text{for}\: 2 x - 1 < - \frac{11}{5} \\- \frac{\sqrt{55} \operatorname{atanh}{\left (\frac{\sqrt{55} \sqrt{1 - 2 x}}{11} \right )}}{55} & \text{for}\: 2 x - 1 > - \frac{11}{5} \end{cases}\right )}{15625} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)**5*(1-2*x)**(1/2)/(3+5*x)**2,x)

[Out]

27*(1 - 2*x)**(9/2)/200 - 8829*(1 - 2*x)**(7/2)/7000 + 107109*(1 - 2*x)**(5/2)/25000 - 144681*(1 - 2*x)**(3/2)
/25000 + 6*sqrt(1 - 2*x)/3125 - 44*Piecewise((sqrt(55)*(-log(sqrt(55)*sqrt(1 - 2*x)/11 - 1)/4 + log(sqrt(55)*s
qrt(1 - 2*x)/11 + 1)/4 - 1/(4*(sqrt(55)*sqrt(1 - 2*x)/11 + 1)) - 1/(4*(sqrt(55)*sqrt(1 - 2*x)/11 - 1)))/605, (
x <= 1/2) & (x > -3/5)))/15625 + 326*Piecewise((-sqrt(55)*acoth(sqrt(55)*sqrt(1 - 2*x)/11)/55, 2*x - 1 < -11/5
), (-sqrt(55)*atanh(sqrt(55)*sqrt(1 - 2*x)/11)/55, 2*x - 1 > -11/5))/15625

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Giac [A]  time = 1.69322, size = 165, normalized size = 1.24 \begin{align*} \frac{27}{200} \,{\left (2 \, x - 1\right )}^{4} \sqrt{-2 \, x + 1} + \frac{8829}{7000} \,{\left (2 \, x - 1\right )}^{3} \sqrt{-2 \, x + 1} + \frac{107109}{25000} \,{\left (2 \, x - 1\right )}^{2} \sqrt{-2 \, x + 1} - \frac{144681}{25000} \,{\left (-2 \, x + 1\right )}^{\frac{3}{2}} + \frac{164}{859375} \, \sqrt{55} \log \left (\frac{{\left | -2 \, \sqrt{55} + 10 \, \sqrt{-2 \, x + 1} \right |}}{2 \,{\left (\sqrt{55} + 5 \, \sqrt{-2 \, x + 1}\right )}}\right ) + \frac{6}{3125} \, \sqrt{-2 \, x + 1} - \frac{\sqrt{-2 \, x + 1}}{15625 \,{\left (5 \, x + 3\right )}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((2+3*x)^5*(1-2*x)^(1/2)/(3+5*x)^2,x, algorithm="giac")

[Out]

27/200*(2*x - 1)^4*sqrt(-2*x + 1) + 8829/7000*(2*x - 1)^3*sqrt(-2*x + 1) + 107109/25000*(2*x - 1)^2*sqrt(-2*x
+ 1) - 144681/25000*(-2*x + 1)^(3/2) + 164/859375*sqrt(55)*log(1/2*abs(-2*sqrt(55) + 10*sqrt(-2*x + 1))/(sqrt(
55) + 5*sqrt(-2*x + 1))) + 6/3125*sqrt(-2*x + 1) - 1/15625*sqrt(-2*x + 1)/(5*x + 3)